Scrapy:如何使用多个搜索项的参数

我正在玩scrapy，现在我尝试搜索不同的关键字，从命令行工具传递参数。 基本上，我想定义一个关键字，爬虫应该搜索包含这个关键字的url。 这是我的命令行:

scrapy crawl myfirst -a nombre="Vermont"

这是我的履带:

class myfirstSpider(CrawlSpider):
    name = 'myfirst'
    allowed_domains= ["leroymerlin.es"]
    start_urls = ["https://www.leroymerlin.es/decoracion-navidena/arboles-navidad?index=%s" % (page_number) for page_number in range(2)]    

    def __init__(self, nombre=None, *args, **kwargs):
        super(myfirstSpider, self).__init__(*args, **kwargs)    
        rules = (
        Rule(LinkExtractor(allow= r'/fp/\*nombre*',), callback = 'parse_item'),)

    def parse_item(self, response):
        items = myfirstItem()

        product_name = response.css ('.titleTechniqueSheet::text').extract()

        items['product_name'] = product_name

        yield items

不幸的是，它不工作… 欢迎帮助，谢谢! 我找到办法了!它适合我:

class myfirstSpider(CrawlSpider):
    name = 'myfirst'
    allowed_domains= ["leroymerlin.es"]
    start_urls = ["https://www.leroymerlin.es/decoracion-navidena/arboles-navidad?index=%s" % (page_number) for page_number in range(2)]    

    def __init__(self, nombre=None, *args, **kwargs):

        self.rules = (
        Rule(LinkExtractor(allow= nombre), callback = 'parse_item'),)
        super(myfirstSpider, self).__init__(*args, **kwargs)

    def parse_item(self, response):
        items = myfirstItem()

        product_name = response.css ('.titleTechniqueSheet::text').extract()

        items['product_name'] = product_name

        yield items

和命令:

scrapy crawl myfirst -a nombre="vermont"

谢谢大家! 问题来源StackOverflow 地址：/questions/59383208/scrapy-how-to-use-arguments-for-multiple-search-terms