我的结果校验代码全11条规则python

第九条规则有点问题， 我做了点小修改。
def verify9(arrange, ds_order_df, o2o_order_df):
    # use the example to verify cal functions
    #mix_path = ["A083","A083","A083","A083","A083","B5800","B7555","B7182","B8307","B8461","A083","A083","A083","B6528","S245","B3266","B3266","B2337","A083","A083","A083","A083","S294","B1940","B6104","B8926","B9072","B6103"]
    #orders = ["F6344","F6360","F6358","F6353","F6354","F6344","F6354","F6353","F6358","F6360","F6349","F6325","F6314","F6349","E0895","E0895","F6325","F6314","F6366","F6345","F6346","F6308","E1088","F6308","F6346","E1088","F6366","F6345"]  
    mix_path = arrange.Addr.tolist()
    orders = arrange.Order_id.tolist()
    mix_arrange_df = pd.DataFrame({ "Addr": mix_path, "Order_id": orders})
    mix_arrange_df["Courier_id"] = arrange.iloc[0].Courier_id
    mix_arrange_df["Arrival_time"] = arrange.iloc[0].Arrival_time
    mix_arrange_df["Departure"] = arrange.iloc[0].Departure
    mix_arrange_df["Amount"] = 0
    pre_e = mix_arrange_df.iloc[0]
    pre_addr = pre_e.Addr
    pre_order = pre_e.Order_id
    pre_departure = arrange.iloc[0].Departure
    if 'F' in pre_order:
        amount = ds_order_df[ds_order_df["Order_id"]==pre_order].Num.values[0]
    elif 'E' in pre_order:
        amount = o2o_order_df[o2o_order_df["Order_id"]==pre_order].Num.values[0]
    new_mix_arrange_df = pd.DataFrame({"Courier_id": [arrange.iloc[0].Courier_id], "Addr": [pre_addr], "Arrival_time": [arrange.iloc[0].Arrival_time], "Departure": [arrange.iloc[0].Departure], "Amount": [amount],  "Order_id": [pre_order]})
    for i in range(1, len(mix_arrange_df)):
        cur_e = mix_arrange_df.iloc
        cur_addr = cur_e.Addr
        cur_order = cur_e.Order_id
        if 'A' in cur_addr:
            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)
            amount = ds_order_df[ds_order_df["Order_id"]==cur_order].Num.values[0]
            departure = arrival_time
        elif 'B' in cur_addr and 'F' in cur_order:
            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)
            amount = -ds_order_df[ds_order_df["Order_id"]==cur_order].Num.values[0]
            departure = arrival_time + cal_proctime(abs(amount))
        elif 'B' in cur_addr and 'E' in cur_order:
            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)
            amount = -o2o_order_df[o2o_order_df["Order_id"]==cur_order].Num.values[0]
            departure = arrival_time + cal_proctime(abs(amount))
        elif 'S' in cur_addr:
            arrival_time = pre_departure + cal_cost(pre_addr, cur_addr)
            amount = o2o_order_df[o2o_order_df["Order_id"]==cur_order].Num.values[0]
            departure = max(time2min(o2o_order_df[o2o_order_df["Order_id"]==cur_order].Pickup_time.values[0]), arrival_time)
        new_mix_arrange_df = new_mix_arrange_df.append(pd.DataFrame({"Courier_id": [arrange.iloc[0].Courier_id], "Addr": [cur_addr], "Arrival_time": [arrival_time], "Departure": [departure], "Amount": [amount],  "Order_id": [cur_order]}))
        cmp_e = arrange.iloc
        if cur_addr != cmp_e.Addr or amount != cmp_e.Amount or arrival_time != cmp_e.Arrival_time or departure != cmp_e.Departure:
            return False
        pre_addr = cur_addr
        pre_departure = departure
    return True

谢谢分享

感觉过了这个校验程序，应该就会有成绩了，自己的结果刚过了校验程序，终于有成绩了

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@marshmallow 你的修改代码已经更新上去了；

另外求高手分享一下算cost的代码