开发者社区> 问答> 正文

javaweb转发forward报错 ?报错

工具eclipse——本意是通过filter过滤,如下:

 public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
            throws IOException, ServletException {
        HttpServletRequest req = (HttpServletRequest) request;
        if (req.getSession().getAttribute("hotproductlist") != null) {
            chain.doFilter(req, response);
        } else {
            req.getRequestDispatcher(req.getContextPath() + "/findHotProduct").forward(req, response);
        }
    }

这里一切正常,但是servlet的forward报错:

 public void doGet(HttpServletRequest request, HttpServletRequest response) throws ServletException, IOException {
        ProductService service=new ProductService();
        List<Product> hotproductlist=new ArrayList<Product>();
        hotproductlist=service.findHotProduct();
        request.getSession().setAttribute("hotproductlist", hotproductlist);
        request.getRequestDispatcher(request.getContextPath()+"/index.jsp").forward(request, response);;
    }

这里的forward报错The method forward(ServletRequest, ServletResponse) in the type RequestDispatcher is not applicable for the arguments (HttpServletRequest, HttpServletRequest)
我觉得是编译器的原因,但是怎么都弄不好,求大佬们指点!!!

展开
收起
爱吃鱼的程序员 2020-06-22 23:18:54 781 0
1 条回答
写回答
取消 提交回答
  • https://developer.aliyun.com/profile/5yerqm5bn5yqg?spm=a2c6h.12873639.0.0.6eae304abcjaIB

    你这个软件有问题的,你要重新安装就好了,

    看一下依赖的jar包版本对不对或者是IDE的问题了

    2020-06-22 23:19:12
    赞同 展开评论 打赏
问答分类:
问答地址:
问答排行榜
最热
最新

相关电子书

更多
Spring Cloud Alibaba - 重新定义 Java Cloud-Native 立即下载
The Reactive Cloud Native Arch 立即下载
JAVA开发手册1.5.0 立即下载