斐波那契数列的实现

public static void testFibonacci1(int n) {
        int a = 1, b=1, c = 0;
        for (int i = 1; i <= n; i++) {
            if (i == 1) {
                System.out.println("第" + i + "等于" + a);
            }else if (i == 2) {
                System.out.println("第" + i + "等于" + b);
            }else {
                c = a+b;
                a = b;
                b = c;
                System.out.println("第" + i + "等于" + c);
            }
        }
    }

斐波那契数列指的是这样一个数列 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233，377，610，987，1597，2584，4181，6765，10946，17711，28657，46368……

特别指出：第0项是0，第1项是第一个1。

这个数列从第三项开始，每一项都等于前两项之和

public class MainClass {
    public static long fibonacci(long number) {
        if ((number == 0) || (number == 1))
            return number;
        else
            return fibonacci(number - 1) + fibonacci(number - 2);
        }
        public static void main(String[] args) {
            for (int counter = 0; counter <= 10; counter++){
            System.out.printf("Fibonacci of %d is: %d\n",
            counter, fibonacci(counter));
        }
    }
}

以上代码运行输出结果为：

Fibonacci of 0 is: 0
Fibonacci of 1 is: 1
Fibonacci of 2 is: 1
Fibonacci of 3 is: 2
Fibonacci of 4 is: 3
Fibonacci of 5 is: 5
Fibonacci of 6 is: 8
Fibonacci of 7 is: 13
Fibonacci of 8 is: 21
Fibonacci of 9 is: 34
Fibonacci of 10 is: 55