python selenium中的多线程

它是一个例子，使用线程来运行独立的浏览器，这些浏览器在列表按钮中填充表单并设置为True，以通知登录按钮已经准备好点击。当列表按钮中的所有浏览器都设置为True时，所有浏览器都会单击按钮。 看起来它几乎是同时运行的——也许只有系统才有一些同时连接这么多的连接。 我使用列表按钮来同步所有线程。每个线程的get号在列表中都有自己的位置。我不使用append(True)，因为我不确定它是否可以是线程安全的。

import time
from selenium import webdriver
from threading import Thread

def func(number):
    driver = webdriver.Chrome()
    #driver.set_window_size(920, 680)
    driver.get(url)

    driver.find_element_by_id("email").send_keys("xx")
    driver.find_element_by_id("pass").send_keys("yy")
    b = driver.find_element_by_id("loginbutton")

    buttons[number] = True
    print(buttons)

    # wait for other buttons
    while not all(buttons):
        pass

    print('click', number)
    b.click()

# ---

url = 'https://www.facebook.com/'

number_of_threads = 5

#buttons = [False * number_of_threads] # create place 
buttons = []

threads = []

for number in range(number_of_threads):
    t = Thread(target=func, args=(number,)) # get number for place in list `buttons`
    t.start()
    threads.append(t)
    buttons.append(False) # create place 

for t in threads:
    t.join()

EDIT:与thread . barrier(5)相同，5个线程必须运行barrier.wait()才能前进。

import time
from selenium import webdriver
from threading import Thread, Barrier

def func(barrier):

    driver = webdriver.Chrome()
    #driver.set_window_size(920, 680)
    driver.get(url)

    driver.find_element_by_id("email").send_keys("xx")
    driver.find_element_by_id("pass").send_keys("yy")
    b = driver.find_element_by_id("loginbutton")

    print('wait for others')
    barrier.wait()

    print('click')
    b.click()

# ---

url = 'https://www.facebook.com/'

number_of_threads = 5

barrier = Barrier(number_of_threads)

threads = []

for _ in range(number_of_threads):
    t = Thread(target=func, args=(barrier,)) 
    t.start()
    threads.append(t)

for t in threads:
    t.join()