从“自己的”子查询列插入#temp表

问题在于value列仅是“ temp”选择的值，不包含在INSERT中。我需要其中两个表，并需要进行联接，因此为了简化-我需要将值插入相同的INSERT和子查询SELECT中。我一直在寻找SO，但是找不到类似的情况。我希望INSERT INTO需要更新，但不确定如何进行更新。任何指向正确方向的指示都会有所帮助。

这是我目前正在测试的代码：

set @inputURL = 'https://sim-ser.blab.kotabl.co/insert_user_in_stored_procedure.asp?hf_autentisatorID=abcd&hf_autentisator_ansvar=150&fld_Username=Pela&fld_Username_m=&fld_Username_e=Boing&fld_Mobilephone=90153150&fld_Workphone=72912121&fle_email=peb.saakolen%40sarvok.kimmone.co&fld_Employee_sn=121181&fld_userident=BESA&fld_hrmID=BESA&hf_klassifisering=Avdelingsleder+(offentlig+administrasjon&hf_ansettelse=Fast+ansatt&hf_workTitle=Enhetsleder&hf_orgID=150&chLukket=on&hf_hprNR=&hf_helseprofession=&tblKompetanse_length=10&hf_pnr=13039026863&fld_start_dato=&fld_slutt_dato=&inst=4&avd=&avd=5&avd=20&avd=23&avd=24&hf_insID=4&hf_avdID=3%2C5%2C20%2C23%2C24&sel_distrikt=5&sel_sone=21&sel_sone=22&sel_sone=23&hf_disID=5&hf_soID=21%2C22%2C23&sel_applikasjon1=42&sel_tilgang1=165&sel_tilgang1=226&sel_tilgang1=225&fld_stillingID=1&fld_ansvar=150&fld_tjeneste=12014&fld_sted=&fld_kommentar=%3E12.11.2019+%3Apaqa%0D%0ADette+er+en+test&chDebug=false' set @URL = REPLACE(@inputURL, '&', ';');

SELECT @URL = (SUBSTRING(@URL,CHARINDEX('?',@URL,0)+1,LEN(@URL)))

CREATE TABLE #app_list ( Id int NOT NULL IDENTITY(1, 1), appname VARCHAR(MAX)/, appId int/ )

INSERT INTO #app_list SELECT * FROM STRING_SPLIT(@URL, ';') where value like '%sel_applikasjon%' (SELECT * FROM #app_list AL CROSS APPLY STRING_SPLIT(appname, '=') AS AN where value NOT LIKE '%sel_applikasjon%' )

SELECT * FROM #app_list /* Want to have value properly inserted as well */

DROP table #app_list