如何清除多个列表或字典?
我有大量的列表和字典，它们需要在每次迭代中清除。我试图写一个函数的GlobalClear，其中有一个列表包含着要清除的列表或字典名称。
Result1={"d11":"1","d12":"2"}
Result2 =["l11","l22"]
def length(name):
print(str(name) + " having length is : "+ str(len(name)))
def GlobalClear():
overallList = ["Result1", "Result2"]
for key in overallList:
list(key).clear()
length(list(key))
print("Prev Length")
length(Result1)
length(Result2)
GlobalClear()
print("Final Length")
length(Result1)
length(Result2)
输出： Prev Length
{'d11': '1', 'd12': '2'} having length is : 2
['l11', 'l22'] having length is : 2
['R', 'e', 's', 'u', 'l', 't', '1'] having length is : 7
['R', 'e', 's', 'u', 'l', 't', '2'] having length is : 7
Final Length
{'d11': '1', 'd12': '2'} having length is : 2
['l11', 'l22'] having length is : 2
预期输出： Prev Length
{'d11': '1', 'd12': '2'} having length is : 2
['l11', 'l22'] having length is : 2
Final Length
{'d11': '1', 'd12': '2'} having length is : 0
['l11', 'l22'] having length is : 0
有没有解决这个问题的好办法？谢谢！
写回答
-
您可以存储对列表本身的引用，并对其调用clear()，而不是存储列表的名称。
Result1={"d11":"1","d12":"2"}
Result2 =["l11","l22"]
def length(name):
print(str(name) + " having length is : "+ str(len(name)))def GlobalClear():
overallList = [Result1, Result2] for key in overallList: key.clear()print("Prev Length")
length(Result1)
length(Result2)
GlobalClear()
print("Final Length")
length(Result1)
length(Result2)
2019-10-11 16:33:58赞同 展开评论 打赏
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