Spark scala让类找不到scala.Any
val schema = df.schema
val x = df.flatMap(r =>
(0 until schema.length).map { idx =>
((idx, r.get(idx)), 1l)}
)
这会产生错误
java.lang.ClassNotFoundException: scala.Any
写回答
-
社区小助手是spark中国社区的管理员，我会定期更新直播回顾等资料和文章干货，还整合了大家在钉群提出的有关spark的问题及回答。一种方法是将所有列强制转换为String。请注意，我正在将代码中的r.get（idx）更改为r.getString（idx）。以下工作。
scala> val df = Seq(("ServiceCent4","AP-1-IOO-PPP","241.206.155.172","06-12-18:17:42:34",162,53,1544098354885L)).toDF("COL1","COL2","COL3","EventTime","COL4","COL5","COL6")
df: org.apache.spark.sql.DataFrame = [COL1: string, COL2: string ... 5 more fields]scala> df.show(1,false) COL1 COL2 COL3 EventTime COL4 COL5 COL6 ServiceCent4 AP-1-IOO-PPP 241.206.155.172 06-12-18:17:42:34 162 53 1544098354885 only showing top 1 row
scala> df.printSchema
root
|-- COL1: string (nullable = true)
|-- COL2: string (nullable = true)
|-- COL3: string (nullable = true)
|-- EventTime: string (nullable = true)
|-- COL4: integer (nullable = false)
|-- COL5: integer (nullable = false)
|-- COL6: long (nullable = false)scala> val schema = df.schema
schema: org.apache.spark.sql.types.StructType = StructType(StructField(COL1,StringType,true), StructField(COL2,StringType,true), StructField(COL3,StringType,true), StructField(EventTime,StringType,true), StructField(COL4,IntegerType,false), StructField(COL5,IntegerType,false), StructField(COL6,LongType,false))scala> val df2 = df.columns.foldLeft(df){ (acc,r) => acc.withColumn(r,col(r).cast("string")) }
df2: org.apache.spark.sql.DataFrame = [COL1: string, COL2: string ... 5 more fields]scala> df2.printSchema
root
|-- COL1: string (nullable = true)
|-- COL2: string (nullable = true)
|-- COL3: string (nullable = true)
|-- EventTime: string (nullable = true)
|-- COL4: string (nullable = false)
|-- COL5: string (nullable = false)
|-- COL6: string (nullable = false)scala> val x = df2.flatMap(r => (0 until schema.length).map { idx => ((idx, r.getString(idx)), 1l) } )
x: org.apache.spark.sql.Dataset[((Int, String), Long)] = [_1: struct<_1: int, _2: string>, _2: bigint]scala> x.show(5,false) _1 _2 [0,ServiceCent4] 1 [1,AP-1-IOO-PPP] 1 [2,241.206.155.172] 1 [3,06-12-18:17:42:34] 1 [4,162] 1 only showing top 5 rows
scala>
2019-07-17 23:23:22赞同 展开评论 打赏
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